Last updated at March 2, 2017 by Teachoo

Transcript

Ex 8.2, 4 ABCD is a trapezium in which AB ∥ DC, BD is a diagonal and E is the mid-point of AD. A line is drawn through E parallel to AB intersecting BC at F. Show that F is the mid-point of BC. Given: ABCD is a trapezium where AB ∥ DC E is the mid point of AD, i.e., AE = DE & EF ∥ AB To prove: F is mid point of BC , i.e., BF = CF Proof: Let EF intersect DB at G. In ∆ ABD E is the mid-point of AD. and EG ∥ AB ∴ G will be the mid-point of DB. Given EF ∥ AB and AB ∥ CD, ∴ EF ∥ CD In ΔBCD, G is the mid-point of side BD. & GF ∥ CD ∴ F is the mid-point of BC. Hence proved

Class 9

Important Questions for Exam - Class 9

- Chapter 1 Class 9 Number Systems
- Chapter 2 Class 9 Polynomials
- Chapter 3 Class 9 Coordinate Geometry
- Chapter 4 Class 9 Linear Equations in Two Variables
- Chapter 5 Class 9 Introduction to Euclid's Geometry
- Chapter 6 Class 9 Lines and Angles
- Chapter 7 Class 9 Triangles
- Chapter 8 Class 9 Quadrilaterals
- Chapter 9 Class 9 Areas of parallelograms and Triangles
- Chapter 10 Class 9 Circles
- Chapter 11 Class 9 Constructions
- Chapter 12 Class 9 Herons Formula
- Chapter 13 Class 9 Surface Areas and Volumes
- Chapter 14 Class 9 Statistics
- Chapter 15 Class 9 Probability

About the Author

Davneet Singh

Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 9 years. He provides courses for Maths and Science at Teachoo.