Last updated at May 29, 2018 by Teachoo

Transcript

Ex 6.1, 5 In the given figure, POQ is a line. Ray OR is perpendicular to line PQ. OS is another ray lying between rays OP and OR. Prove that ∠ROS = 1/2 (∠QOS – ∠POS ) Since OR ⊥ PQ Hence, ∠ ROP = 90° & ∠ ROQ = 90° We can say that ∠ ROP = ∠ ROQ ∠ POS + ∠ ROS = ∠ ROQ ∠ POS + ∠ ROS = ∠ QOS – ∠ ROS ∠ SOR + ∠ ROS = ∠ QOS – ∠ POS 2(∠ ROS) = ∠ QOS – ∠ POS ∠ ROS = 1/2 ("∠ QOS – ∠ POS" ) ∠ ROS = 1/2 ("∠ QOS – ∠ POS" ) Hence proved

Class 9

Important Questions for Exam - Class 9

- Chapter 1 Class 9 Number Systems
- Chapter 2 Class 9 Polynomials
- Chapter 3 Class 9 Coordinate Geometry
- Chapter 4 Class 9 Linear Equations in Two Variables
- Chapter 5 Class 9 Introduction to Euclid's Geometry
- Chapter 6 Class 9 Lines and Angles
- Chapter 7 Class 9 Triangles
- Chapter 8 Class 9 Quadrilaterals
- Chapter 9 Class 9 Areas of parallelograms and Triangles
- Chapter 10 Class 9 Circles
- Chapter 11 Class 9 Constructions
- Chapter 12 Class 9 Herons Formula
- Chapter 13 Class 9 Surface Areas and Volumes
- Chapter 14 Class 9 Statistics
- Chapter 15 Class 9 Probability

About the Author

Davneet Singh

Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 9 years. He provides courses for Maths and Science at Teachoo.