Question 1 - Examples - Chapter 7 Class 8 Comparing Quantities
Last updated at Dec. 16, 2024 by Teachoo
Last updated at Dec. 16, 2024 by Teachoo
Question 1 (Method 1) The price of a scooter was Rs 34,000 last year. It has increased by 20% this year. What is the price now? Given, Old Price of scooter = 34000 Percentage increase = 20% Percentage increase = (πΌππππππ π ππ πππππ)/(πππ πππππ) Γ 100 20 = (πΌππππππ π ππ πππππ)/34000 Γ 100 20 = (πΌππππππ π ππ πππππ)/340 20 Γ 340 = Increase in price 6800 = Increase in Price β΄ Increase in Price = 6800 Now, New price = Old Price + Increase in price = 34000 + 6800 = 40800 β΄ New price is now Rs 40,800 Question 1 (Method 2) The price of a scooter was Rs 34,000 last year. It has increased by 20% this year. What is the price now? Given, Old Price of scooter = 34000 Percentage increase = 20% Increase in price = Percentage increase Γ Old Price = 20% Γ 34000 = 20/100 Γ 3400 = 20 Γ 340 = 6800 β΄ Increase in Price = 6800 Now, New price = Old Price + Increase in price = 34000 + 6800 = 40800 β΄ New price is now Rs 40,800
Examples
Example 1 (ii)
Example 1 (iii) Important
Example 2 Important
Example 3
Example 4
Example 5
Example 6 β GST (Page Number - 124)
Example 7 (Page no. 126) Important
Example 8
Example 9
Example 10 Important
Question 1 You are here
Question 2
Question 3 Important
Question 4 Important
Question 5
Question 6 Important
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Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science and Computer Science at Teachoo