1. Class 10
  2. Solutions of Sample Papers for Class 10 Boards
  3. CBSE Class 10 Sample Paper for 2019 Boards
Check sibling questions

Question 28 (Or 1st) - CBSE Class 10 Sample Paper for 2019 Boards - Solutions of Sample Papers for Class 10 Boards

Last updated at Dec. 16, 2024 by Teachoo

Question 28 (OR 1 st question)

The median of the following data is 525. Find the values of x and y if the total frequency is 100.

Class Interval

Frequency

0 – 100

2

100 – 200

5

200 – 300

x

300 – 400

12

400 – 500

17

500 – 600

20

600 – 700

y

700 – 800

9

800 – 900

7

900 – 100

4

Transcript

Question 28 (OR 1st question) The median of the following data is 525. Find the values of x and y if the total frequency is 100. Given that total frequency is 100 So, Sum of frequency = 100 2 + 5 + x + 12 + 17 + 17 + 20 + y + 8 + 7 + 4 = 100 76 + x + y = 100 x + y = 100 – 76 x + y = 24 Now, to find values of x and y, We first find median Since Median is 525 500 – 600 is the median class Median = l + (𝑛/2 − 𝑐𝑓)/𝑓 × h Where l = lower limit of median class = 500 h = class-interval = 100 − 0 = 100 n = ∑▒𝑓𝑖 = 100 cf = cumulative frequency of the class before median class = 36 + x f = frequency of the median class = 20 Now, Median = l + (𝑛/2 −𝑐𝑓)/𝑓 × h 525 = 500 + (100/2 − (36 + 𝑥))/20 × 100 525 – 500 = (50 − (36 + 𝑥))/20 × 100 25 = (14 − 𝑥)/20 × 100 25 = (14 – x) × 5 25 = 70 – 5x 5x = 70 – 25 5x = 45 x = 45/9 x = 5 Now, from (1) x + y = 24 Putting x = 5 5 + y = 24 y = 24 – 5 y = 19 Thus, x = 5, y = 19
  1. Class 10
  2. Solutions of Sample Papers for Class 10 Boards

    3. CBSE Class 10 Sample Paper for 2019 Boards

    CBSE Class 10 Sample Paper for 2018 Boards →
CBSE Class 10 Sample Paper for 2018 Boards →
Class 10
Solutions of Sample Papers for Class 10 Boards

About the Author

Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science and Computer Science at Teachoo