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Question 3 (OR 1 st question)

Write the value of cot 2 ⁡θ - 1/sin 2 ⁡θ


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Question 3 (OR 1st question) Write the value of cot^2⁡𝜃−1/sin^2⁡𝜃 cot^2⁡𝜃−1/sin^2⁡𝜃 Writing cot θ = cos⁡𝜃/sin⁡𝜃 = (cos⁡𝜃/sin⁡𝜃 )^2−1/sin^2⁡𝜃 = cos^2⁡𝜃/sin^2⁡𝜃 −1/sin^2⁡𝜃 = (cos^2⁡𝜃 − 1)/sin^2⁡𝜃 Now, sin2 θ + cos2 θ = 1 cos2 θ = 1 – sin2 θ = ((1 − sin^2⁡𝜃) − 1)/sin^2⁡𝜃 = (− sin^2⁡𝜃)/sin^2⁡𝜃 = –1

  1. Class 10
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Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science and Computer Science at Teachoo