1. Chapter 5 Class 8 Squares and Square Roots
  2. Serial order wise
  3. Ex 5.4
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Ex 5.4, 5 (i) - Chapter 5 Class 8 Squares and Square Roots

Last updated at Dec. 16, 2024 by Teachoo

Transcript

Ex 5.4, 5 Find the least number which must be added to each of the following numbers so as to get a perfect square. Also find the square root of the perfect square so obtained. (i) 525 Here, Remainder = 41 Since remainder is not 0, So, 525 is not a perfect square We need to find the least number that must be added to 525 so as to get a perfect square Now, Thus, we add 232 – 525 to the number ∴ Number to added = 232 − 525 = 529 – 525 = 4 Thus, Perfect square = 525 + 4 Let’s check Thus, we add 4 to 525 to get a perfect square. Perfect square = 529 & Square root of 529 = 23
  1. Chapter 5 Class 8 Squares and Square Roots
  2. Serial order wise

    3. Ex 5.4

    Examples →
Examples →
Chapter 5 Class 8 Squares and Square Roots
Serial order wise

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Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science and Computer Science at Teachoo