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Find ∫e x   √(1 + sin ⁡2x )/(1 + cos ⁡2x ) dx

This is a question of CBSE Sample Paper - Class 12 - 2017/18.

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Transcript

Question 9 Find 1 ^ (1 + sin 2 )/(1 + cos 2 ) dx 1 ^ (1 + 2 )/(1 + 2 ) dx Putting sin 2x = 2 sin x cos x cos 2x = 2 cos2 x 1 = 1 ^ (1 + 2 sin cos )/(1 + (2 cos^2 1)) dx = 1 ^ (1 + 2 sin cos )/(2 cos^2 ) dx Putting 1 = sin2 x + cos2 x = 1 ^ (sin^2 + cos^2 + 2 sin cos )/(2 cos^2 ) dx = 1 (( + )^2 )/(2 2 )dx = 1/2 1 ^ (sin /( 2 )+cos /( 2 )) = 1/2 1 ("sec sec tan x " ) = 1/2 ^ sec x + c [ ^ ( ( )+ ^ ( )) = ^ ( )+ ] Using (a + b)2 = a2 + b2 + 2ab where a = sin x , b = cos x = 1 ^ (( + )^2 )/(2 2 ) dx = 1/2 1 ^ (( + ))/ 2 dx = 1/2 1 ^ (sin /( 2 )+cos /( 2 )) = 1/2 1 ^ (sin /( ) 1/cos +1/cos ) = 1/2 1 ^ (tan sec +sec ) = 1/2 1 ^ (sec +tan sec ) Using 1 ^ ( ( )+ ^ ( )) = ^ ( )+ Where f(x) = sec x = / ^ sec x + c

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Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science and Computer Science at Teachoo