Find the approximate change in the value of 1/x 2 , when x changes from x = 2 to x = 2.002
This is a question of CBSE Sample Paper - Class 12 - 2017/18.
You can download the question paper here https://www.teachoo.com/cbse/sample-papers/
Last updated at Dec. 16, 2024 by Teachoo
This is a question of CBSE Sample Paper - Class 12 - 2017/18.
You can download the question paper here https://www.teachoo.com/cbse/sample-papers/
Question 8 Find the approximate change in the value of 1/๐ฅ^2 , when x changes from x = 2 to x = 2.002 Let y = 1/๐ฅ^2 We need to find change in value of y when x changes from 2 to 0.002 โด โx = 2.002 โ 2 = 0.002 We need to find โy Now, โy = ๐๐ฆ/๐๐ฅ โx โy = ๐(1/๐ฅ^2 )/๐๐ฅ โx โy = ๐(๐ฅ^(โ2) )/๐๐ฅ ร 0.002 โy = โ2 ร xโ3 ร 0.002 Since we go from x = 2 to x = 2.002 We put x = 2 in โy โy = โ2 ร 2โ3 ร 0.002 โy = โ2 ร 1/2^3 ร 0.002 โy = โ2 ร 1/2^3 ร 2/1000 โy = (โ1)/2000 โy = โ 0.0005 โด y decreases by 0.0005
CBSE Class 12 Sample Paper for 2018 Boards
Question 1 Important
Question 2 Important
Question 3
Question 4
Question 5
Question 6 Important
Question 7 Important
Question 8 You are here
Question 9 Important
Question 10
Question 11 Important
Question 12
Question 13 Important
Question 14 Important
Question 15
Question 16 Important
Question 17
Question 18 Important
Question 19
Question 20 Important
Question 21 Important
Question 22
Question 23
Question 24 Important
Question 25
Question 26 Important
Question 27
Question 28 Important
Question 29
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Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science and Computer Science at Teachoo