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Find the approximate change in the value of 1/x 2 , when x changes from x = 2 to x = 2.002

This is a question of CBSE Sample Paper - Class 12 - 2017/18.

You can download the question paper here  https://www.teachoo.com/cbse/sample-papers/



Transcript

Question 8 Find the approximate change in the value of 1/๐‘ฅ^2 , when x changes from x = 2 to x = 2.002 Let y = 1/๐‘ฅ^2 We need to find change in value of y when x changes from 2 to 0.002 โˆด โˆ†x = 2.002 โ€“ 2 = 0.002 We need to find โˆ†y Now, โˆ†y = ๐‘‘๐‘ฆ/๐‘‘๐‘ฅ โˆ†x โˆ†y = ๐‘‘(1/๐‘ฅ^2 )/๐‘‘๐‘ฅ โˆ†x โˆ†y = ๐‘‘(๐‘ฅ^(โˆ’2) )/๐‘‘๐‘ฅ ร— 0.002 โˆ†y = โ€“2 ร— xโ€“3 ร— 0.002 Since we go from x = 2 to x = 2.002 We put x = 2 in โˆ†y โˆ†y = โ€“2 ร— 2โ€“3 ร— 0.002 โˆ†y = โ€“2 ร— 1/2^3 ร— 0.002 โˆ†y = โ€“2 ร— 1/2^3 ร— 2/1000 โˆ†y = (โˆ’1)/2000 โˆ†y = โ€“ 0.0005 โˆด y decreases by 0.0005

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About the Author

Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science and Computer Science at Teachoo