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Find the inverse of the matrix [-3 2 5 -3] . Hence,  find the matrix P satisfying the matrix equation P [-3 2 5 -3] = [1 2 2 -1] .

This is a question of CBSE Sample Paper - Class 12 - 2017/18.

You can download the question paper here  https://www.teachoo.com/cbse/sample-papers/



Transcript

Question 6 Find the inverse of the matrix [■8(−3&2@5&−3)]. Hence, find the matrix P satisfying the matrix equation P [■8(−3&2@5&−3)] = [■8(1&2@2&−1)]. Let A = [■8(−3&2@5&−3)] We know that A-1 = 1/(|A|) adj A exists when |A|≠ 0 |A| = |■8(−3&2@5&−3)| = (–3) × (–3) – 5 × 2 = 9 – 10 = –1 Since |A|≠ 0, A–1 exists Calculating adj A A =[■8(−3&2@5&−3)] adj(A) = [■8(−3&2@5&−3)] = [■8(−3&−2@−5&−3)] Calculating A–1 A-1 = 1/(|A|) adj A = 𝟏/(−𝟏) [■8(−3&−2@−5&−3)] = −1[■8(−3&−2@−5&−3)] = [■8(−1 × −3&−1 × −2@−1 × −5&−1 × −3)] = [■8(𝟑&𝟐@𝟓&𝟑)] Now, P [■8(−3&2@5&−3)] = [■8(1&2@2&−1)] PA = [■8(1&2@2&−1)] P = [■8(1&2@2&−1)]A–1 Putting value of A–1 P = [■8(1&2@2&−1)][■8(3&2@5&3)] P = [■8(1(3)+2(5)&1(2)+2(3)@2(3)+(−1)5&2(2)+(−1)3)] P = [■8(3+10&2+6@6−5&4−3)] P = [■8(𝟏𝟑&𝟖@𝟏&𝟏)]

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About the Author

Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science and Computer Science at Teachoo