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Ex 1.3, 14 Let f : R โ€“ {(โˆ’4)/3} โ†’ R be a function defined as f (x) = 4๐‘ฅ/(3๐‘ฅ + 4) The inverse of f is map g: Range f โ†’ R โ€“ {(โˆ’4)/3}given by (A) g (y) = 3๐‘ฆ/(3โˆ’4๐‘ฆ) (B) g (y) = 4๐‘ฆ/(4โˆ’3๐‘ฆ) (C) g (y) = 4๐‘ฆ/(3โˆ’4๐‘ฆ) (D) g (y) = 3๐‘ฆ/(4โˆ’3๐‘ฆ) f(x) = 4๐‘ฅ/(3๐‘ฅ + 4) Calculating inverse Take f(x) = y Hence, equation becomes y = 4๐‘ฅ/(3๐‘ฅ + 4) y(3x + 4) = 4x 3xy + 4y = 4x 3xy โ€“ 4x = โ€“ 4y x(3y โ€“ 4) = โ€“ 4y x = (โˆ’4๐‘ฆ)/(3๐‘ฆ โˆ’ 4) x = (โˆ’4๐‘ฆ)/(โˆ’1(โˆ’3๐‘ฆ + 4)) x = 4๐‘ฆ/((4 โˆ’ 3๐‘ฆ)) So, inverse of f = 4๐‘ฆ/((4 โˆ’ 3๐‘ฆ)) โˆด g(y) = 4๐‘ฆ/((4 โˆ’ 3๐‘ฆ)) Hence, B is the correct answer

  1. Chapter 1 Class 12 Relation and Functions
  2. Serial order wise

About the Author

Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science and Computer Science at Teachoo