1. Chapter 4 Class 12 Determinants
  2. Serial order wise
  3. Properties of Determinant
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Question 2 - Properties of Determinant - Chapter 4 Class 12 Determinants

Last updated at Dec. 16, 2024 by Teachoo

Transcript

Question 2 Using the property of determinants and without expanding, prove that: |■8(a−b&b−c&c−𝑎@b−c&c−a&a−b@c−a&a−b&b−c)| = 0 |■8(a−b&b−c&c−𝑎@b−c&c−a&a−b@c−a&a−b&b−c)| Making first row 0 by Applying R1 →R1 + R2 + R3 = |■8(a−b+b−c+c−a&b−c+c−a+a−b&c−a+a−b+b−c@b−c&c−a&a−b@c−a&a−b&b−c)| = |■8(0&0&0@b−c&c−a&a−b@c−a&a−b&b−c)| = 0 |■8(c−a&a−b@a−b&b−c)| – 0 |■8(b−c&a−b@c−a&b−c)| + 0 |■8(b−c&c−a@c−a&a−b)| = 0 – 0 + 0 = 0 = R.H.S Thus, L.H.S = R.H.S Hence proved
  1. Chapter 4 Class 12 Determinants
  2. Serial order wise

    3. Properties of Determinant

    Finding determinant of a 2x2 matrix →
Finding determinant of a 2x2 matrix →
Chapter 4 Class 12 Determinants
Serial order wise

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Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science and Computer Science at Teachoo