Question 5 - Examples - Chapter 8 Class 11 Sequences and Series
Last updated at Dec. 16, 2024 by Teachoo
Last updated at Dec. 16, 2024 by Teachoo
Question 5 Insert 6 number between 3 and 24 such that the resulting sequence is an AP We know that to insert n number between a and b common difference = d = (๐ โ ๐)/(๐ + 1) Here, We need to insert 6 numbers between 3 and 24 So, b = 24 , a = 3 & number of terms to be inserted = n = 6 Therefore, d = (24 โ 3 )/(6 + 1) = 21/7 = 3 a = 3, d = 3 & b = 24 Hence six numbers between 3 and 24 are 6, 9, 12, 15, 13 & 21.
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Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science and Computer Science at Teachoo