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Question 4 (Case Based MCQ) - NCERT Exemplar - MCQs - Chapter 12 Class 12 Linear Programming

Last updated at Dec. 16, 2024 by Teachoo

The feasible solution for a LPP is shown in Fig. 12.12. Let Z = 3x – 4y be the objective function. Minimum of Z occurs at

(A) (0, 0)                                (B) (0, 8)   

(C) (5, 0)                               (D) (4, 10)

 

This question is similar to Ex 12.2, 11 - Chapter 12 Class 12 - Linear Programming

Transcript

Question 4 The feasible solution for a LPP is shown in Fig. 12.12. Let Z = 3x – 4y be the objective function. Minimum of Z occurs at (A) (0, 0) (B) (0, 8) (C) (5, 0) (D) (4, 10) Checking value of Z = 3x – 4y at corner points Thus, Min Z = −32 at (0, 8) So, the correct answer is (B)
  1. Chapter 12 Class 12 Linear Programming
  2. Serial order wise

    3. NCERT Exemplar - MCQs

    Forming equations and solving →
Forming equations and solving →
Chapter 12 Class 12 Linear Programming
Serial order wise

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Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science and Computer Science at Teachoo