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Question 45 (Case Based Question) - CBSE Class 10 Sample Paper for 2022 Boards - Maths Standard [MCQ] - Solutions of Sample Papers for Class 10 Boards

Last updated at Dec. 16, 2024 by Teachoo

The zeroes of the polynomial r(t) = −12t 2 + (k − 3)t + 48 are negative of each other. Then k is

(a) 3   (b) 0   (c) −1.5   (d) −3

Transcript

Question 45 The zeroes of the polynomial r(t) = −12t2 + (k − 3)t + 48 are negative of each other. Then k is (a) 3 (b) 0 (c) −1.5 (d) −3 Given r(t) = −12t2 + (k − 3)t + 48 Since zeros are negative of each other Let zeroes of r(t) be 𝛼 and −𝛼 Now, Sum of Zeroes = (−𝑏)/𝑎 0 = (−(𝒌 − 𝟑))/(−𝟏𝟐) 0 = ((𝑘 − 3))/12 0 = k − 3 3 = k k = 3 So, the correct answer is (a)
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Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science and Computer Science at Teachoo