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Question 19 - CBSE Class 10 Sample Paper for 2022 Boards - Maths Standard [MCQ] - Solutions of Sample Papers for Class 10 Boards

Last updated at Dec. 16, 2024 by Teachoo

One equation of a pair of dependent linear equations is –5x + 7y = 2. The second equation can be

(a) 10x + 14y + 4 = 0   (b) –10x – 14y + 4 = 0

(c) –10x + 14y + 4 = 0   (d) 10x – 14y = –4

 

This question is inspired from Question 11 - MCQs from NCERT Exemplar - Chapter 3 Class 10 - Pair of Linear Equations in Two Variables

 

Transcript

Question 19 One equation of a pair of dependent linear equations is –5x + 7y = 2. The second equation can be (a) 10x + 14y + 4 = 0 (b) –10x – 14y + 4 = 0 (c) –10x + 14y + 4 = 0 (d) 10x – 14y = –4 Given equation −5x + 7y − 2 = 0 Therefore, a1 = −5, b1 = 7 , c1 = –2 Since we want a dependent line, it means the lines are coincident For Coincident lines 𝒂𝟏/𝒂𝟐 = 𝒃𝟏/𝒃𝟐 = 𝒄𝟏/𝒄𝟐 Since, a1 = −5 , b1 = 7 , c1 = −2 a2, b2, c2 can be a2 = −10 , b2 = 14 , c2 = −4 Thus, a coincident line is −10x + 14y − 4 = 0 10x − 14y = −4 So, the correct answer is (D)
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Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science and Computer Science at Teachoo