1. Chapter 7 Class 9 Triangles
  2. Serial order wise
  3. Examples
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Question 1 - Examples - Chapter 7 Class 9 Triangles

Last updated at Dec. 13, 2024 by Teachoo

Transcript

Question 1 D is a point on side BC of ABC such that AD = AC (see figure). Show that AB > AD. AD = AC So, ACD = ADC Now, ADC is an exterior angle for ABD. ADC = ABD + BAD So, ADC > ABD ACD > ABD AB > AC AB > AD Hence proved

  1. Chapter 7 Class 9 Triangles
  2. Serial order wise

    3. Examples

    Theorems →
Theorems →
Chapter 7 Class 9 Triangles
Serial order wise

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Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science and Computer Science at Teachoo