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Ex 12.2, 5 - Chapter 12 Class 7 Algebraic Expressions
Last updated at March 30, 2023 by Teachoo
Ex 12.2
Ex 12.2, 1 (i)
Ex 12.2, 1 (ii) Important
Ex 12.2, 1 (iii)
Ex 12.2, 1 (iv) Important
Ex 12.2, 1 (v) Important
Ex 12.2, 1 (vi)
Ex 12.2, 2 (i)
Ex 12.2, 2 (ii) Important
Ex 12.2, 2 (iii)
Ex 12.2, 2 (iv)
Ex 12.2, 2 (v) Important
Ex 12.2, 2 (vi)
Ex 12.2, 2 (vii) Important
Ex 12.2, 2 (viii) Important
Ex 12.2, 2 (ix)
Ex 12.2, 2 (x) Important
Ex 12.2, 3 (i)
Ex 12.2, 3 (ii) Important
Ex 12.2, 3 (iii)
Ex 12.2, 3 (iv)
Ex 12.2, 3 (v) Important
Ex 12.2, 3 (vi)
Ex 12.2, 3 (vii) Important
Ex 12.2, 3 (viii) Important
Ex 12.2, 4 (a)
Ex 12.2, 4 (b) Important
Ex 12.2, 5 You are here
Ex 12.2, 6 (a)
Ex 12.2, 6 (b) Important
Transcript
Ex 12.2, 5 What should be taken away from 3x2 – 4y2 + 5xy + 20 to obtain – x2 – y2 + 6xy + 20? Given that (3x2 – 4y2 + 5xy + 20) − Expression = (– x2 – y2 + 6xy + 20) (3x2 – 4y2 + 5xy + 20) − (– x2 – y2 + 6xy + 20) = Expression Expression = (3x2 – 4y2 + 5xy + 20) − (−x2 − y2 + 6xy + 20) Putting like terms below like terms & subtracting Answer is 4x2 − 3y2 − xy
