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Ex 12.2
Ex 12.2, 1 (ii) Important
Ex 12.2, 1 (iii)
Ex 12.2, 1 (iv) Important
Ex 12.2, 1 (v) Important
Ex 12.2, 1 (vi)
Ex 12.2, 2 (i)
Ex 12.2, 2 (ii) Important
Ex 12.2, 2 (iii)
Ex 12.2, 2 (iv)
Ex 12.2, 2 (v) Important
Ex 12.2, 2 (vi)
Ex 12.2, 2 (vii) Important
Ex 12.2, 2 (viii) Important
Ex 12.2, 2 (ix)
Ex 12.2, 2 (x) Important
Ex 12.2, 3 (i)
Ex 12.2, 3 (ii) Important
Ex 12.2, 3 (iii)
Ex 12.2, 3 (iv)
Ex 12.2, 3 (v) Important
Ex 12.2, 3 (vi)
Ex 12.2, 3 (vii) Important
Ex 12.2, 3 (viii) Important
Ex 12.2, 4 (a)
Ex 12.2, 4 (b) Important
Ex 12.2, 5
Ex 12.2, 6 (a)
Ex 12.2, 6 (b) Important You are here
Last updated at March 22, 2023 by Teachoo
Ex 12.2, 6 (b) From the sum of 4 + 3x and 5 – 4x + 2x2, subtract the sum of 3x2 – 5x and –x2 + 2x + 5. Sum of (4 + 3x) and (5 − 4x+ 2x2) is given by Sum of (3x2 − 5x) and (−x2 + 2x + 5) is given by Subtracting (2x2 − 3x + 5) from (9 − x + 2x2) Answer is 4 + 2x i.e. 2x + 4