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Ex 12.2
Ex 12.2, 1 (ii) Important
Ex 12.2, 1 (iii)
Ex 12.2, 1 (iv) Important
Ex 12.2, 1 (v) Important
Ex 12.2, 1 (vi)
Ex 12.2, 2 (i)
Ex 12.2, 2 (ii) Important
Ex 12.2, 2 (iii)
Ex 12.2, 2 (iv)
Ex 12.2, 2 (v) Important
Ex 12.2, 2 (vi)
Ex 12.2, 2 (vii) Important
Ex 12.2, 2 (viii) Important
Ex 12.2, 2 (ix)
Ex 12.2, 2 (x) Important
Ex 12.2, 3 (i)
Ex 12.2, 3 (ii) Important
Ex 12.2, 3 (iii)
Ex 12.2, 3 (iv)
Ex 12.2, 3 (v) Important
Ex 12.2, 3 (vi) You are here
Ex 12.2, 3 (vii) Important
Ex 12.2, 3 (viii) Important
Ex 12.2, 4 (a)
Ex 12.2, 4 (b) Important
Ex 12.2, 5
Ex 12.2, 6 (a)
Ex 12.2, 6 (b) Important
Last updated at March 22, 2023 by Teachoo
Ex 12.2, 3 Subtract: (vi) – x2 + 10x – 5 from 5x – 10 (5x − 10) − (−x2 + 10x − 5) = 5x − 10 + x2 − 10x + 5 = x2 + 5x − 10x + 5 − 10 = x2 + x (5 − 10) + (5 − 10) = x2 + x (−5) + (−5) = x2 − 5x − 5