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Ex 12.2, 3 (i) - Chapter 12 Class 7 Algebraic Expressions
Last updated at March 23, 2023 by Teachoo
Ex 12.2
Ex 12.2, 1 (i)
Ex 12.2, 1 (ii) Important
Ex 12.2, 1 (iii)
Ex 12.2, 1 (iv) Important
Ex 12.2, 1 (v) Important
Ex 12.2, 1 (vi)
Ex 12.2, 2 (i)
Ex 12.2, 2 (ii) Important
Ex 12.2, 2 (iii)
Ex 12.2, 2 (iv)
Ex 12.2, 2 (v) Important
Ex 12.2, 2 (vi)
Ex 12.2, 2 (vii) Important
Ex 12.2, 2 (viii) Important
Ex 12.2, 2 (ix)
Ex 12.2, 2 (x) Important
Ex 12.2, 3 (i) You are here
Ex 12.2, 3 (ii) Important
Ex 12.2, 3 (iii)
Ex 12.2, 3 (iv)
Ex 12.2, 3 (v) Important
Ex 12.2, 3 (vi)
Ex 12.2, 3 (vii) Important
Ex 12.2, 3 (viii) Important
Ex 12.2, 4 (a)
Ex 12.2, 4 (b) Important
Ex 12.2, 5
Ex 12.2, 6 (a)
Ex 12.2, 6 (b) Important
Transcript
Ex 12.2, 3 Subtract: (i) –5y2 from y2 y2 − (−5y2) = y2 + 5y2 = y2 (1 + 5) = y2 (6) = 6y2 Ex 12.2, 3 (Method 1) Subtract: (viii) 4pq – 5q2 – 3p2 from 5p2 + 3q2 – pq (5p2 + 3q2 – pq) − (4pq – 5q2 – 3p2) = 5p2 + 3q2 – pq − 4pq + 5q2 + 3p2 = 5p2 + 3p2 + 3q2 + 5q2 – pq − 4pq = p2 (5 + 3) + q2 (3 + 5) + pq (−1 − 4) = p2 (8) + q2 (8) + pq (−5) = 8p2 + 8q2 − 5pq
