Question 3 Subtract: (i) –5y2 from y2 y2 − (−5y2) = y2 + 5y2 = y2 (1 + 5) = y2 (6) = 6y2 Question 3 (Method 1) Subtract: (viii) 4pq – 5q2 – 3p2 from 5p2 + 3q2 – pq (5p2 + 3q2 – pq) − (4pq – 5q2 – 3p2) = 5p2 + 3q2 – pq − 4pq + 5q2 + 3p2 = 5p2 + 3p2 + 3q2 + 5q2 – pq − 4pq = p2 (5 + 3) + q2 (3 + 5) + pq (−1 − 4) = p2 (8) + q2 (8) + pq (−5) = 8p2 + 8q2 − 5pq

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Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 13 years. He provides courses for Maths, Science, Social Science, Physics, Chemistry, Computer Science at Teachoo.

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