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  1. Chapter 13 Class 7 Exponents and Powers
  2. Serial order wise

Transcript

Example 11 Simplify and write the answer in the exponential form (i) (3^7/3^2 )ร—3^5 (3^7/3^2 )ร—3^5 Using, ๐‘Ž^๐‘š/๐‘Ž^๐‘› = ๐‘Ž^(๐‘š โˆ’ ๐‘›) = (37 โˆ’ 2) ร— 35 = 35 ร— 35 Using am ร— an = am ร— n = 35 + 5 = 310 Example 11 Simplify and write the answer in the exponential form (ii) 23 ร— 22 ร— 55 23 ร— 22 ร— 55 = (23 ร— 22) ร— 55 Using am ร— an = am + n = (23 + 2) ร— 55 = 25 ร— 55 Using am ร— bm = (a ร— b)m = (2 ร— 5)5 = 105 Example 11 Simplify and write the answer in the exponential form (iii) (62 ร— 64) รท 63 (62 ร— 64 ) รท 63 = ((6^2 ร—ใ€– 6ใ€—^4))/6^3 Using am ร— an = am + n = ((6^(2 + 4)))/6^3 = 6^6/6^3 Using ๐‘Ž^๐‘š/๐‘Ž^๐‘› = am โˆ’ n = 66 โˆ’ 3 = 63 Example 11 Simplify and write the answer in the exponential form (iv) [(22)3 ร— 36] ร— 56 [(22)3 ร— 36] รท 56 Using (am)n = am ร— n = [22 ร— 3 ร— 36] ร— 56 = 26 ร— 36 ร— 56 Using am ร— bm = (a ร— b)m = (2 ร— 3 ร— 5)6 = (6 ร— 5)6 = 306 Example 11 Simplify and write the answer in the exponential form (v) 82 รท 23 8^2/2^3 = (2 ร— 2 ร— 2)^2/2^3 = (2^3 )^2/2^3 (As 8 = 2 ร— 2 ร— 2) Using (am)n = am ร— n = 2^(3 ร— 2)/2^3 = 2^6/2^3 = 26โˆ’3 = 23

About the Author

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Davneet Singh
Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 9 years. He provides courses for Maths and Science at Teachoo.