# Example 11 (iv) - Chapter 13 Class 7 Exponents and Powers

Last updated at Sept. 7, 2021 by Teachoo

Last updated at Sept. 7, 2021 by Teachoo

Transcript

Example 11 Simplify and write the answer in the exponential form (iv) [(22)3 × 36] × 56 [(22)3 × 36] ÷ 56 Using (am)n = am × n = [22 × 3 × 36] × 56 = 26 × 36 × 56 Using am × bm = (a × b)m = (2 × 3 × 5)6 = (6 × 5)6 = 306

Examples

Example 1

Example 2

Example 3

Example 4

Example 5 (i) Important

Example 5 (ii)

Example 5 (iii)

Example 5 (iv)

Example 6

Example 7

Example 8 (i)

Example 8 (ii)

Example 8 (iii)

Example 9 (i)

Example 9 (ii)

Example 10

Example 11 (i) Important

Example 11 (ii)

Example 11 (iii)

Example 11 (iv) You are here

Example 11 (v)

Example 12 (i) Important

Example 12 (ii)

Example 12 (iii)

Example 13 (i)

Example 13 (ii)

Example 13 (iii)

Example 13 (iv)

About the Author

Davneet Singh

Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 10 years. He provides courses for Maths and Science at Teachoo.