Ex 9.2, 8 - Chapter 9 Class 8 Mensuration

Last updated at August 13, 2026 by

Ex 9.2, 8 - The lateral surface area of a hollow cylinder is 4224 cm2 - Ex 9.2

part 2 - Ex 9.2, 8 - Ex 9.2 - Serial order wise - Chapter 9 Class 8 Mensuration
 

Remove Ads

Transcript

Ex 9.2, 8 The lateral surface area of a hollow cylinder is 4224〖 𝑐𝑚〗^2. It is cut along its height and formed a rectangular sheet of width 33 cm. Find the perimeter of rectangular sheet?Given that Hollow cylinder is converted into a rectangular sheet So, Area of cylinder and sheet must be the same ∴ Curved Surface Area of hollow cylinder = Area of rectangular sheet 4224 = Length × Breadth 4224 = 𝑙 × 33 4224/33 = 𝑙 𝑙 = 4224/33 𝒍 = 128 cm Now, Perimeter of sheet = 2 × (Length + Breadth) = 2 × (128 + 33) = 2 × 161 = 322 cm

Davneet Singh's photo - Co-founder, Teachoo

Made by

Davneet Singh

Davneet Singh is an IIT Kanpur graduate and has been teaching for 16+ years. At Teachoo, he breaks down Maths, Science and Computer Science into simple steps so students understand concepts deeply and score with confidence.

Many students prefer Teachoo Black for a smooth, ad-free learning experience.