Ex 11.2, 7 The floor of a building consists of 3000 tiles which are rhombus shaped and each of its diagonals are 45 cm and 30 cm in length. Find the total cost of polishing the floor, if the cost per 𝑚^2 is Rs 4.
Given,
Total Number of tiles used = 3000
Since tile is in the shape of rhombus
and Diagonals are 45 cm and 30 cm
Thus,
d1 = 30 cm
d2 = 45 cm
Area of one tile = Area of rhombus
= 1/2 × d1 × d2
= 1/2 × 30 × 45
= 15 × 45
= 675 cm2
Area of 3000 tiles = 3000 × Area of 1 tile
= 3000 × 675
= 2025000 cm2
Now, we need to find cost.
Since cost is given per m2
We need to convert the area into m2
Area = 2025000 cm2
= 2025000 × (1/100)^2 m2
= 2025000/10000 m2
= 202.5 m2
Now
Cost of Polishing 1 m2 = 4
Cost of Publishing 202.5 m2 = 4 × 202.5
= 4 × 2025/10
= 4 × 405/2
= 810
∴ Total cost of polishing the floor = Rs 810

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 13 years. He provides courses for Maths, Science, Social Science, Physics, Chemistry, Computer Science at Teachoo.

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