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Learn in your speed, with individual attention - Teachoo Maths 1-on-1 Class


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Ex 9.1, 4 (Method 1) The diagonal of a quadrilateral shaped field is 24 m and the perpendiculars dropped on it from the remaining opposite vertices are 8 m and 13 m. Find the area of the field.Given BD = 24 m And, Length of Perpendicular dropped on BD h1 = 13 m & h2 = 8 m Now, Area of quadrilateral ABCD = Area of ΔADB + Area of ΔBDC = 𝟏/𝟐 × 𝑩𝑫 × 𝒉_𝟏+𝟏/𝟐 × 𝑩𝑫 × 𝒉_𝟐 = 1/2 × 24 × 13+ 1/2 × 24 × 8 = 12 × 13+12 × 8 = 𝟏𝟐 × (𝟏𝟑+𝟖) = 12 × 21 = 252 m2 ∴ Area of quadrilateral = 252 m2 Ex 9.1, 4 (Method 2) The diagonal of a quadrilateral shaped field is 24 m and the perpendiculars dropped on it from the remaining opposite vertices are 8 m and 13 m. Find the area of the field.Given Length of diagonal = d = 24 m Length of Perpendicular dropped on BD h1 = 13m & h2 = 8 m Now, Area of ABCD = 𝒅/𝟐 (h1 + h2) = 24/2 (13 + 8) = 12 × 21 = 252 Area of quadrilateral = 252 m2

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Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 13 years. He provides courses for Maths, Science, Social Science, Physics, Chemistry, Computer Science at Teachoo.