Chapter 9 Class 8 Mensuration

Serial order wise

Last updated at April 16, 2024 by Teachoo

Ex 9.2, 1 There are two cuboidal boxes as shown in the adjoining figure. Which box requires the lesser amount of material to make?The box with lesser total surface area will require lesser amount of material to make. Letβs find total surface area of both boxes Total Surface Area of Box (a) This box is a cuboid with Length = l = 60 cm Breadth = b = 60 cm Height = h = 60 cm Total surface area of box = Total surface area of cuboid = π(ππ+ππ+ππ) Total Surface Area of Box (b) This box is a cube with Side = a = 50 cm Total surface area of box = Total surface area of cube = ππ^π = 6Γ(50)^2 = 6Γ50Γ50 = 6Γ2500 = πππππ ππ^π = 2(60Γ40+40Γ50+50Γ60) = 2(2400+2000+3000) = 2Γ74000. = ππππππ ππ^π Since total surface area of box (a) is lesser than the total surface area of box (b). β΄ Box (a) requires lesser amount of material to make.