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  1. Chapter 11 Class 8 Mensuration
  2. Serial order wise

Transcript

Ex 11.3, 2 A suitcase with measures 80 cm ร— 48 cm ร— 24 cm is to be covered with a tarpaulin cloth. How many meters of tarpaulin of width 96 cm is required to cover 100 such suitcases? Given, Length of suitcase = ๐‘™ = 80 cm Breadth of suitcase = ๐‘ = 48 cm & Height of suitcase = โ„Ž = 24 cm As tarpaulin cloth covers the suitcase. โˆด Area of cloth required to cover 1 suitcase = Total surface area of 1 suitcase Total surface area of 1 suitcase = Total surface area of cuboid = 2(๐‘™๐‘+๐‘โ„Ž+โ„Ž๐‘™) = 2(80ร—48+48ร—24+24ร—80) = 2(3840+1152+1920) = 2ร—6912 = 13824 ๐‘๐‘š^2 Now, we need to find how many meters of tarpaulin of width 96 cm is required to cover 100 such suitcases So, Area of tarpaulin = 100 ร— Area of 1 suitcase Since Tarpaulin is a rectangle with Width = 96 cm and Length we need to find So, Area of tarpaulin = 100 ร— Area of 1 suitcase 96 ร— Length = 100 ร— 13824 Length = 100 ร— 13824/96 Length = 100 ร— 6912/48 = 100 ร— 3456/24 = 100 ร— 1728/12 = 100 ร— 144 Length = 14400 cm Length = 14400 cm Length = 14400 ร— 1/100 m Length = 144 m โˆด 144 m of cloth is required.

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Davneet Singh
Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 9 years. He provides courses for Maths and Science at Teachoo.