Ex 11.3, 2 A suitcase with measures 80 cm × 48 cm × 24 cm is to be covered with a tarpaulin cloth. How many meters of tarpaulin of width 96 cm is required to cover 100 such suitcases?
Given,
Length of suitcase = 𝑙 = 80 cm
Breadth of suitcase = 𝑏 = 48 cm
& Height of suitcase = ℎ = 24 cm
As tarpaulin cloth covers the suitcase.
∴ Area of cloth required to cover 1 suitcase
= Total surface area of 1 suitcase
Total surface area of 1 suitcase
= Total surface area of cuboid
= 2(𝑙𝑏+𝑏ℎ+ℎ𝑙)
= 2(80×48+48×24+24×80)
= 2(3840+1152+1920)
= 2×6912
= 13824 𝑐𝑚^2
Now,
we need to find how many meters of tarpaulin of width 96 cm is required to cover 100 such suitcases
So,
Area of tarpaulin = 100 × Area of 1 suitcase
Since Tarpaulin is a rectangle
with Width = 96 cm
and Length we need to find
So,
Area of tarpaulin = 100 × Area of 1 suitcase
96 × Length = 100 × 13824
Length = 100 × 13824/96
Length = 100 × 6912/48 = 100 × 3456/24 = 100 × 1728/12 = 100 × 144
Length = 14400 cm
Length = 14400 cm
Length = 14400 × 1/100 m
Length = 144 m
∴ 144 m of cloth is required.

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 13 years. He provides courses for Maths, Science, Social Science, Physics, Chemistry, Computer Science at Teachoo.

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