Ex 9.1, 3 Length of the fence of a trapezium shaped field ABCD is 120 m. If BC = 48 m, CD = 17 m and AD = 40 m, find the area of this field. Side AB is perpendicular to the parallel sides AD and BC.BC = 48 m, CD = 17 m, DA = 40m
& Given Length of fence of Trapezium = 120 m
Now,
Perimeter of trapezium = Length of fence
AB + BC + CD + DA = 120
AB + 48 + 17 + 40 = 120
AB + 105 = 120
AB = 120 − 105
AB = 15 m
Since AB ⊥ BC,
AB is the height of the trapezium
Now,
Area of trapezium = 𝟏/𝟐 (𝒂 + b) × h
Putting h = Height = AB = 15 m
a = length of Parallel side = 40 m
& b = Length of other Parallel side = 48 m
Area = 𝟏/𝟐 (40 + 48) × 15
= 1/2 × 88 × 15
= 44 × 15
= 660 m2
Area of field = 660 m2

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science, Social Science, Physics, Chemistry, Computer Science at Teachoo.

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