# Question 7 - Examples - Chapter 9 Class 7 Perimeter and Area

Last updated at April 16, 2024 by Teachoo

Examples

Example 1

Example 2 Important

Example 3 Important

Example 4 (i)

Example 4 (ii) Important

Example 5

Example 6 Important

Example 7 Important

Example 8

Example 9

Example 10 Important

Example 11 Important

Example 12 Important

Example 13

Example 14 Important

Question 1 Deleted for CBSE Board 2024 Exams

Question 2 Deleted for CBSE Board 2024 Exams

Question 3 Important Deleted for CBSE Board 2024 Exams

Question 4 Important Deleted for CBSE Board 2024 Exams

Question 5 Deleted for CBSE Board 2024 Exams

Question 6 Deleted for CBSE Board 2024 Exams

Question 7 Important Deleted for CBSE Board 2024 Exams You are here

Question 8 Important Deleted for CBSE Board 2024 Exams

Last updated at April 16, 2024 by Teachoo

Question 7 A path 5 m wide runs along inside a square park of side 100 m. Find the area of the path. Also find the cost of cementing it at the rate of Rs 250 per 10 m2. Area of path = Area of larger square − Area of smaller square Finding side of both squares Side of larger square = 100 m Now, 5 m path is constructed all around inside the larger square ∴ Side of smaller square = Side of larger square − 2 × 5 = 100 − 10 = 90 m Larger square Side = a = 100 m Area of larger square = a × a = 100 × 100 = 10,000 m2 Smaller square Side = a = 90 m Area of smaller square = a × a = 90 × 90 = 81,00 m2 Now, Area of path = Area of larger square − Area of smaller square = 10,000− 81,00 = 1,900 m2 Now, Cost of cementing path for 10 m2 = Rs 250 Cost of cementing path for 1 m2 = Rs 250/10 Cost of cementing path for 1900 m2 = Rs 250/10 × 1900 = Rs 25 × 1900 = Rs 47, 500 Thus, Area of path is 1900 m2 & Cost of cementing is Rs 47,500