# Example 5 - Chapter 11 Class 7 Perimeter and Area

Last updated at Dec. 6, 2021 by Teachoo

Examples

Example 1

Example 2

Example 3 Important

Example 4 Important

Example 5 You are here

Example 6

Example 7 Important

Example 8 Important

Example 9 (i)

Example 9 (ii) Important

Example 10

Example 11 Important

Example 12 Important

Example 13

Example 14

Example 15 Important

Example 16 Important

Example 17 Important

Example 18

Example 19 Important

Example 20

Example 21 Important

Example 22 Important

Example 5 The area of a square and a rectangle are equal. If the side of the square is 40 cm and the breadth of the rectangle is 25 cm, find the length of the rectangle. Also, find the perimeter of the rectangle. Square Side of square = a = 4 cm Area of square = a2 = (40)2 = 1600 cm2 Rectangle Length of rectangle = l = ? Breadth of rectangle = b = 25 cm Area of rectangle = l × b = l × 25 = 25l cm2 Given, Area of square = Area of rectangle 1600 = 25l 25l = 1600 25l = 1600/25 l = 320/5 l = 64 cm ∴ Length of given rectangle is of 64 cm Also, we need to find perimeter of rectangle Perimeter of rectangle Length of rectangle = l = 64 cm Breadth of rectangle = b = 25 cm Perimeter = 2 (l + b) = 2 (64 + 25) = 2 × 89 = 178 cm ∴ Perimeter of rectangle is 178 cm