Question 4 - Examples - Chapter 9 Class 7 Perimeter and Area

Last updated at April 16, 2024 by

Example 4 - A wire is in the shape of a square of side 10 cm. If

Example 4 - Chapter 11 Class 7 Perimeter and Area - Part 2
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Example 4 - Chapter 11 Class 7 Perimeter and Area - Part 4

Transcript

Question 4 A wire is in the shape of a square of side 10 cm. If the wire is rebent into a rectangle of length 12 cm, find its breadth. Which encloses more area, the square or the rectangle? We convert Square wire into rectangle So, length of wire will be same ∴ Perimeter of square = Perimeter of rectangle Square Side of square = a = 10 cm Perimeter = 4a = 4 × 10 = 40 cm Rectangle Length of rectangle = l = 12 cm Breadth of rectangle = b = ? Perimeter = 2 (l + b) = 2 (12 + b) = 12 cm Here, ∴ Perimeter of square = Perimeter of rectangle 40 = 2 (12 + b) 40/2 = 12 + b 20 = 12 + b 20 − 12 = b 8 = b b = 8 ∴ Breadth of rectangle is of 8 cm. Now, We need to find whose area is bigger Finding area Square Area = a × a = 10 × 10 = 100 cm2 Rectangle Area = l × b = 12 × 8 = 96 cm2 So, Area of square is greater then area of rectangle

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Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science, Social Science, Physics, Chemistry, Computer Science at Teachoo.