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Question 6 - Examples - Chapter 9 Class 7 Perimeter and Area

Last updated at May 29, 2023 by

Example 20 - A rectangular park is 45 m long and 30 m wide. A path

Example 20 - Chapter 11 Class 7 Perimeter and Area - Part 2
Example 20 - Chapter 11 Class 7 Perimeter and Area - Part 3 Example 20 - Chapter 11 Class 7 Perimeter and Area - Part 4

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Question 6 A rectangular park is 45 m long and 30 m wide. A path 2.5 m wide is constructed outside the park. Find the area of the path. Here, Area of path = Area of larger rectangle − Area of smaller rectangle Finding length and breadth of both rectangles Smaller rectangle Length of smaller rectangle = 45 m Breadth of smaller rectangle = 30 m Larger Rectangle 2.5 m wide path runs all around outside smaller rectangle. ∴ Length of larger rectangle = Length of smaller rectangle + 2 × 2.5 = 45 + 5 = 50 m Breadth of larger rectangle = Breadth of smaller rectangle + 2 × 2.5 = 30 + 5 = 35 m Larger rectangle Length = l = 50 m Breadth = b = 35 m Area of larger rectangle = l × b = 50 × 35 = 1750 m2 Smaller rectangle Length = l = 45 m Breadth = b = 30 m Area of smaller rectangle = l × b = 45 × 30 = 1350 m2 Now, Area of path = Area of larger rectangle − Area of smaller rectangle = 17500 − 1350 = 400 m2 ∴ Area of path is 400 m2

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Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 13 years. He provides courses for Maths, Science, Social Science, Physics, Chemistry, Computer Science at Teachoo.