![Example 20 - Chapter 11 Class 7 Perimeter and Area - Part 2](https://d1avenlh0i1xmr.cloudfront.net/1ebdd517-2109-4bf2-b543-1e85de65b1bb/slide46.jpg)
![Example 20 - Chapter 11 Class 7 Perimeter and Area - Part 3](https://d1avenlh0i1xmr.cloudfront.net/1f9b9953-24ab-4c1f-ad56-d6b48e270f3b/slide47.jpg)
![Example 20 - Chapter 11 Class 7 Perimeter and Area - Part 4](https://d1avenlh0i1xmr.cloudfront.net/7f7bfbc1-e577-4be6-83cd-64d7a5687b53/slide48.jpg)
Examples
Last updated at April 16, 2024 by Teachoo
Question 6 A rectangular park is 45 m long and 30 m wide. A path 2.5 m wide is constructed outside the park. Find the area of the path. Here, Area of path = Area of larger rectangle − Area of smaller rectangle Finding length and breadth of both rectangles Smaller rectangle Length of smaller rectangle = 45 m Breadth of smaller rectangle = 30 m Larger Rectangle 2.5 m wide path runs all around outside smaller rectangle. ∴ Length of larger rectangle = Length of smaller rectangle + 2 × 2.5 = 45 + 5 = 50 m Breadth of larger rectangle = Breadth of smaller rectangle + 2 × 2.5 = 30 + 5 = 35 m Larger rectangle Length = l = 50 m Breadth = b = 35 m Area of larger rectangle = l × b = 50 × 35 = 1750 m2 Smaller rectangle Length = l = 45 m Breadth = b = 30 m Area of smaller rectangle = l × b = 45 × 30 = 1350 m2 Now, Area of path = Area of larger rectangle − Area of smaller rectangle = 17500 − 1350 = 400 m2 ∴ Area of path is 400 m2