Ex 11.4, 9 - The figure represents a rectangular lawn with a circular

Ex 11.4, 9 - Chapter 11 Class 7 Perimeter and Area - Part 2
Ex 11.4, 9 - Chapter 11 Class 7 Perimeter and Area - Part 3
Ex 11.4, 9 - Chapter 11 Class 7 Perimeter and Area - Part 4
Ex 11.4, 9 - Chapter 11 Class 7 Perimeter and Area - Part 5 Ex 11.4, 9 - Chapter 11 Class 7 Perimeter and Area - Part 6


Transcript

Question 9 The adjoining figure represents a rectangular lawn with a circular flower bed in the middle. Find: (i) the area of the whole land Area of whole land = Area of rectangle Now, Length of rectangular lawn = l = 10 m Breadth of rectangular lawn = b = 5 m Area of whole land = l × b = 10 × 5 = 50 m2 ∴ Area of whole land is 50 m2 Question 9 The adjoining figure represents a rectangular lawn with a circular flower bed in the middle. Find: (ii) the area of the flower bed Area of flower bed = Area of circle Radius of flower bed = r = 2 m Area of flower bed = 𝜋r2 = 3.14 × (2)2 = 3.14 × 4 = 314/100 × 4 = 1256/100 = 12.56 cm2 ∴ Area of flower bed is 12.56 m2 Question 9 The adjoining figure represents a rectangular lawn with a circular flower bed in the middle. Find: (iii) the area of the lawn excluding the area of the flower bed Required area = Area of whole land − Area of flower bed = 50 − 12.56 = 50 − 1256/100 = (50 × 100 − 1256)/100 = (5000 − 1256)/100 = 3744/100 = 3744 m2 ∴ Required area is 37.44 m2 Question 9 The adjoining figure represents a rectangular lawn with a circular flower bed in the middle. Find: (iv) the circumference of the flower bed. Circumference of flower bed = Circumference of circle = 2𝜋r = 2 × 3.14 × 2 = 2 × 314/100 × 2 = 1256/100 = 12.56 m ∴ Circumference of flower bed is 12.56 m

Ask a doubt
Davneet Singh's photo - Co-founder, Teachoo

Made by

Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science, Social Science, Physics, Chemistry, Computer Science at Teachoo.