Question 4 - Area of Path and Cross roads - Worksheet - Chapter 9 Class 7 Perimeter and Area
Last updated at April 16, 2024 by Teachoo
Area of Path and Cross roads - Worksheet
Question 2 Important Deleted for CBSE Board 2025 Exams
Question 3 Deleted for CBSE Board 2025 Exams
Question 4 Important Deleted for CBSE Board 2025 Exams You are here
Question 5 Deleted for CBSE Board 2025 Exams
Question 6 Important Deleted for CBSE Board 2025 Exams
Question 7 Deleted for CBSE Board 2025 Exams
Question 8 Important Deleted for CBSE Board 2025 Exams
Question 9 Deleted for CBSE Board 2025 Exams
Question 10 (i) Important Deleted for CBSE Board 2025 Exams
Question 10 (ii) Deleted for CBSE Board 2025 Exams
Question 11 Important Deleted for CBSE Board 2025 Exams
Area of Path and Cross roads - Worksheet
Last updated at April 16, 2024 by Teachoo
Question 4 A verandah of width 2.25 m is constructed all along outside a room which is 5.5 m long and 4 m wide. Find: (i) the area of the verandah. Here, Area of verandah = Area of larger rectangle − Area of smaller rectangle Finding length and breadth of both rectangles Smaller rectangle Length of smaller rectangle = 5.5 m Breadth of smaller rectangle = 4 m Larger Rectangle 2.25 m of verandah has been constructed all around outside of smaller rectangle ∴ Length of larger rectangle = Length of smaller rectangle + 2 × 2.25 = 5.5 + 2 (225/100) = 5.5 + 450/100 = 55/10 + 45/10 = (55 + 45)/10 = 100/10 = 10 m ∴ Breadth of larger rectangle = Breadth of smaller rectangle + 2 × 2.25 = 4 + 2 (225/100) = 4 + 450/100 = 4 + 45/10 = (4 × 10 + 45)/10 = (40 + 45)/10 = 85/10 = 8.5 m Larger rectangle Length = l = 10 m Breadth = b = 8.5 m Area of larger rectangle = l × b = 10 × 8.5 = 10 × 85/10 = 85 m2 Smaller rectangle Length = l = 5.5 m Breadth = b = 4 m Area of smaller rectangle = l × b = 5.5 × 4 = 55/10 × 4 = 55/5 × 2 = 11 × 2 Now, Area of verandah = Area of larger rectangle − Area of smaller rectangle = 85 − 22 = 63 m2 ∴ Area of path is 63 m2 Question 4 A verandah of width 2.25 m is constructed all along outside a room which is 5.5 m long and 4 m wide. Find: (ii) the cost of cementing the floor of the verandah at the rate of Rs 200 per m2. Cost of cementing verandah in 1 m2 = Rs 200 Cost of cementing verandah in 63 m2 = Rs 200 × 63 = Rs 12,600 ∴ It will cost Rs 12,600 for it’s cementing Cost of cementing verandah in 1 m2 = Rs 200 Cost of cementing verandah in 63 m2 = Rs 200 × 63 = Rs 12,600 ∴ It will cost Rs 12,600 for it’s cementing Cost of cementing verandah in 1 m2 = Rs 200 Cost of cementing verandah in 63 m2 = Rs 200 × 63 = Rs 12,600 ∴ It will cost Rs 12,600 for it’s cementing Cost of cementing verandah in 1 m2 = Rs 200 Cost of cementing verandah in 63 m2 = Rs 200 × 63 = Rs 12,600 ∴ It will cost Rs 12,600 for it’s cementing Cost of cementing verandah in 1 m2 = Rs 200 Cost of cementing verandah in 63 m2 = Rs 200 × 63 = Rs 12,600 ∴ It will cost Rs 12,600 for it’s cementing Cost of cementing verandah in 1 m2 = Rs 200 Cost of cementing verandah in 63 m2 = Rs 200 × 63 = Rs 12,600 ∴ It will cost Rs 12,600 for it’s cementing