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  1. Chapter 8 Class 8 Comparing Quantities
  2. Serial order wise
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Ex 8.3, 12 A scooter was bought at Rs 42,000. Its value depreciated at the rate of 8% per annum. Find its value after one year.Scooter was bought for 42000 So, P = 42000 Here, 8% P.A is depreciated Depreciated means value is decreased. So, we Put a Minus Sign in Rate ∴ Rate = −8% Since the rate is compounded, we use the formula A = P (1+𝑅/100)^𝑛 Here P = 42000 R = – 8% P.A n = Number of Years n = 1 Putting values in formula A = 42,000 (1+(−8)/100)^1 = 42000 (1−8/100) = 42000 ((100 − 8)/100) = 42000 (92/100) = 420 × 92 = 38,640 ∴ Value of scooter after one year = Rs 38,640

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Davneet Singh
Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 8 years. He provides courses for Maths and Science at Teachoo. You can check his NCERT Solutions from Class 6 to 12.