Ex 8.3, 12 A scooter was bought at Rs 42,000. Its value depreciated at the rate of 8% per annum. Find its value after one year.Scooter was bought for 42000
So, P = 42000
Here, 8% P.A is depreciated
Depreciated means value is decreased.
So, we Put a Minus Sign in Rate
∴ Rate = −8%
Since the rate is compounded,
we use the formula
A = P (1+𝑅/100)^𝑛
Here P = 42000
R = – 8% P.A
n = Number of Years
n = 1
Putting values in formula
A = 42,000 (1+(−8)/100)^1
= 42000 (1−8/100)
= 42000 ((100 − 8)/100)
= 42000 (92/100)
= 420 × 92
= 38,640
∴ Value of scooter after one year = Rs 38,640

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 13 years. He provides courses for Maths, Science, Social Science, Physics, Chemistry, Computer Science at Teachoo.

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