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  1. Chapter 8 Class 8 Comparing Quantities
  2. Serial order wise
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Ex 8.3, 1 (a) Calculate the amount and compound interest on (a) Rs 10,800 for 3 years at 12 1/2 % per annum compounded annually Given, Principal (P) = 10, 800 Time = 3 years Rate (R) = 12 1/2 per Annum compounded Annually. = 25/2 % Amount (A) = P (1+๐‘…/100)^๐‘› = 10,800 (1+(25/2)/100)^3 = 10,800 (1+25/(2 ร— 100))^3 = 10,800 (1+1/(2 ร—4))^3 = 10,800 (1+1/8)^3 = 10,800 ((8 + 1)/8)^3 = 10,800 ร— (9/8)^3 = 10,800 ร— (9 ร— 9 ร— 9 )/(8 ร— 8 ร— 8 ) = 5400 ร— (9 ร— 9 ร— 9 )/(4 ร— 8 ร— 8 ) = 2700 ร— (9 ร— 9 ร— 9 )/(2 ร— 8 ร—8 ) = 2700 ร— (81 ร— 9 )/(2 ร— 64 ) = 2700 ร— 729/(128 ) = 2700 ร— 729/(128 ) = 1968300/(128 ) = 15377.34 โˆด Amount after 3 years = Rs 15,377.34 Now, Amount = Principal + Interest 15377.34 = 10800 + Interest 15377.34 โ€“ 10800 + Interest 4577.34 = Interest โˆด Interest = Rs 4,577.34

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Davneet Singh
Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 8 years. He provides courses for Maths and Science at Teachoo. You can check his NCERT Solutions from Class 6 to 12.