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  1. Chapter 8 Class 8 Comparing Quantities
  2. Serial order wise
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Ex 8.3, 1 (b) Calculate the amount and compound interest on (b) Rs 18,000 for 2 1/2 years at 10% per annum compounded annually. Given, Principal = 18,000 Time (n) = 2 1/2 years Rate (R) = 10 % per Annum. Since n is in fraction, we use the formula. Compound interest for 2 1/2 years = Compound interest for 2 years + Simple interest for 1/2 ๐‘ฆ๐‘’๐‘Ž๐‘Ÿ. Compound interest for 2 years P = 18,000 N = 2 R = 10% Amount = P (1+๐‘…/100)^๐‘› Putting values = 18,000 (1+10/100)^2 = 18000 (1+1/10)^2 = 18000 ((10 + 1)/10)^2 = 18000 (11/10)^2 = 18000 ร— 121/100 = 180 ร— 121 = 21,780 Since Amount = Principal + Interest 21,780 = 18000 + Interest 21,780 โˆ’ 18,000 = Interest 3780 = Interest Interest = 3780 โˆด Interest for 2 years = Rs 3780 & Amount after 2 years = Rs 21780 Simple interest for the next ๐Ÿ/๐Ÿ year Principal will be the amount after 1 year P = 21,780 R = 10% T = 1/2 year Interest = (๐‘ƒ ร—๐‘… ร— ๐‘‡)/100 = (21780 ร— 10 ร— 1/2)/100 = (21780 ร— 10)/(2 ร— 100) = 21780/2 = 1089 โˆด Simple interest for next 1/2 year = Rs 1089 Now, Interest for 2 1/2 years = Compound interest for 2 years + Simple Interest for 1/2 year = 3780 + 1089 = 4869 Amount = Principal + interest = 18000 + 4869 = 22869 โˆด Amount = Rs 22,869 & Interest = Rs 4,869

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