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  1. Chapter 8 Class 7 Comparing Quantities
  2. Serial order wise
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Example 15 If Rs 250 is to be divided amongst Ravi, Raju and Roy, so that Ravi gets two parts, Raju three parts and Roy five parts. How much money will each get? What will it be in percentages? Given, Ravi gets gets two parts, Raju three parts and Roy five parts So, Ravi : Raju : Roy = 2 : 3 : 5 Total parts = 2 + 3 + 5 = 10 Total money = Rs 250 Ravi Number of parts = 2 Total parts = 10 Money received = (๐‘๐‘ข๐‘š๐‘๐‘’๐‘Ÿ ๐‘œ๐‘“ ๐‘๐‘Ž๐‘Ÿ๐‘ก๐‘ )/(๐‘‡๐‘œ๐‘ก๐‘Ž๐‘™ ๐‘๐‘Ž๐‘Ÿ๐‘ก๐‘ ) ร— Total money = 2/10 ร— 250 = 2/1 ร— 25 = Rs 50 Percentage of money = 2/10 ร— 100% = 20% Raju Number of parts = 2 Total parts = 10 Money received = (๐‘๐‘ข๐‘š๐‘๐‘’๐‘Ÿ ๐‘œ๐‘“ ๐‘๐‘Ž๐‘Ÿ๐‘ก๐‘ )/(๐‘‡๐‘œ๐‘ก๐‘Ž๐‘™ ๐‘๐‘Ž๐‘Ÿ๐‘ก๐‘ ) ร— Total money = 3/10 ร— 250 = 3/1 ร— 25 = Rs 75 Percentage of money = 3/10 ร— 100% = 30% Roy Number of parts = 2 Total parts = 10 Money received = (๐‘๐‘ข๐‘š๐‘๐‘’๐‘Ÿ ๐‘œ๐‘“ ๐‘๐‘Ž๐‘Ÿ๐‘ก๐‘ )/(๐‘‡๐‘œ๐‘ก๐‘Ž๐‘™ ๐‘๐‘Ž๐‘Ÿ๐‘ก๐‘ ) ร— Total money = 5/10 ร— 250 = 5/1 ร— 25 = Rs 125 Percentage of money = 5/10 ร— 100% = 50%

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Davneet Singh
Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 8 years. He provides courses for Maths and Science at Teachoo. You can check his NCERT Solutions from Class 6 to 12.