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  1. Chapter 8 Class 7 Comparing Quantities
  2. Serial order wise
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Ex 8.1, 1 Find the ratio of: (a) Rs 5 to 50 paise To find ratio, we convert both numbers to same units Rs 5 = 5 ร— 100 paise = 500 paise Rs 5 to 50 paise Ratio = (๐‘…๐‘  5)/(50 ๐‘๐‘Ž๐‘–๐‘ ๐‘’) = (500 ๐‘๐‘Ž๐‘–๐‘ ๐‘’)/(50 ๐‘๐‘Ž๐‘–๐‘ ๐‘’) = 500/50 = 10/1 = 10 : 1 โˆด Required ratio is 10 : 1 Ex 8.1, 1 Find the ratio of: (b) 15 kg to 210 g To find ratio, we convert both numbers to same units 15 kg = 15 ร— 1000 g 15 kg = 15,000 g 15 g to 210 g Ratio = (15 ๐‘˜๐‘”)/(210 ๐‘”) = (15000 ๐‘”)/(210 ๐‘”) = 15000/210 = 1500/21 = 500/7 = 500 : 7 โˆด Required ratio is 500 : 7 Ex 8.1, 1 Find the ratio of: (c) 9 m to 27 cm To find ratio, we convert both numbers to same units 9 m = 9 ร— 100 cm = 900 cm 9m to 27 cm Ratio = (9 ๐‘š)/(27 ๐‘๐‘š) = (900 ๐‘๐‘š)/(27 ๐‘๐‘š) = 900/27 = 300/9 = 100/3 = 100 : 3 โˆด Required ratio is 100 : 3 Ex 8.1, 1 Find the ratio of: (d) 30 days to 36 hours To find ratio, we convert both numbers to same units 30 days = 30 ร— 24 hours = 720 hours 30 days to 36 hours Ratio = (30 ๐‘‘๐‘Ž๐‘ฆ๐‘ )/(36 โ„Ž๐‘œ๐‘ข๐‘Ÿ๐‘ ) = (720 โ„Ž๐‘œ๐‘ข๐‘Ÿ๐‘ )/(36 โ„Ž๐‘œ๐‘ข๐‘Ÿ๐‘ ) (1 day = 24 hours) = 720/36 = 360/18 = 180/9 = 20/1 = 20 : 1 โˆด Required ratio is 20 : 1

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Davneet Singh
Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 8 years. He provides courses for Maths and Science at Teachoo. You can check his NCERT Solutions from Class 6 to 12.