Ex 8.1, 1 - Chapter 8 Class 7 Comparing Quantities - Part 5

Advertisement

Ex 8.1, 1 - Chapter 8 Class 7 Comparing Quantities - Part 6

Advertisement

  1. Chapter 8 Class 7 Comparing Quantities
  2. Serial order wise

Transcript

Ex 8.1, 1 Find the ratio of: (c) 9 m to 27 cm To find ratio, we convert both numbers to same units 9 m = 9 ร— 100 cm = 900 cm 9m to 27 cm Ratio = (9 ๐‘š)/(27 ๐‘๐‘š) = (900 ๐‘๐‘š)/(27 ๐‘๐‘š) = 900/27 = 300/9 = 100/3 = 100 : 3 โˆด Required ratio is 100 : 3

About the Author

Davneet Singh's photo - Teacher, Engineer, Marketer
Davneet Singh
Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 10 years. He provides courses for Maths and Science at Teachoo.