Example 3 - Practical Geometry

Last updated at July 27, 2026 by

Example 3 - Construct XYZ if it is given that XY = 6 cm, ZXY = 30

Example 3 - Chapter 10 Class 7 Practical Geometry - Part 2
Example 3 - Chapter 10 Class 7 Practical Geometry - Part 3 Example 3 - Chapter 10 Class 7 Practical Geometry - Part 4 Example 3 - Chapter 10 Class 7 Practical Geometry - Part 5

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Example 3 Construct ∆XYZ if it is given that XY = 6 cm, m∠ZXY = 30° and m∠XYZ = 100°. First we draw a rough sketch We follow these steps Steps of construction 1. Draw a line segment XY of length 6 cm 2. Now, we draw 30° from point X Check Ex 11.1, 3 (i) of Chapter 11 Class 9 NCERT to see how to draw 30° 3. Now, we draw 100° from point Y (Using protractor) 4. Let point Z be the point where the two rays intersect and label the sides Thus, Δ XYZ is the required triangle

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