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  1. Chapter 10 Class 7 Practical Geometry
  2. Serial order wise


Example 2 Construct a triangle PQR, given that PQ = 3 cm, QR = 5.5 cm and ∠PQR = 60°. First we draw a rough sketch We follow these steps Steps of construction 1. Draw a line segment QR of length 5.5 cm 2. Now, we draw 60° from point Q Check Construction 11.3 of Chapter 11 Class 9 NCERT to see how to draw 60° 3. Taking Q as center, 3 cm as radius, we draw an arc Let the point where arc intersects the ray be point P 4. Join PR and label the sides Thus, Δ PQR is the required triangle

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Davneet Singh
Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 9 years. He provides courses for Maths and Science at Teachoo.