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  1. Chapter 10 Class 7 Practical Geometry
  2. Serial order wise
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Transcript

Ex 10.3, 1 Construct ∆DEF such that DE = 5 cm, DF = 3 cm and m∠EDF = 90°. First we draw a rough sketch To construct it, We follow these steps Steps of construction 1. Draw a line segment DF of length 3 cm 2. Now, we draw 90° from point D Check Ex 11.1, 1 of Chapter 11 Class 9 NCERT to see how to draw 90° 3. Taking D as center, 5 cm as radius, we draw an arc Let the point where arc intersects the ray be point E 4. Join EF and label the sides Thus, Δ DEF is the required triangle

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Davneet Singh
Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 8 years. He provides courses for Maths and Science at Teachoo. You can check his NCERT Solutions from Class 6 to 12.