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  1. Chapter 10 Class 7 Practical Geometry
  2. Serial order wise
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Transcript

Ex 10.5, 1 Construct the right angled ∆PQR, where m∠Q = 90°, QR = 8cm and PR = 10 cm. First we draw a rough sketch We follow these steps Steps of construction 1. Draw a line segment QR of length 8 cm 2. Now, we draw 90° from point Q Check Ex 11.1, 1 of Chapter 11 Class 9 NCERT to see how to draw 90° 3. Taking R as center, 10 cm as radius, we draw an arc Let the point where arc intersects the ray be point P 4. Join PR and label the sides Thus, Δ PQR is the required triangle

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Davneet Singh
Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 8 years. He provides courses for Maths and Science at Teachoo. You can check his NCERT Solutions from Class 6 to 12.