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Chapter 10 Class 7 Practical Geometry
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Ex 10.5, 1 - Construct the right angled PQR, where Q = 90, QR = 8 cm

Ex 10.5, 1 - Chapter 10 Class 7 Practical Geometry - Part 2
Ex 10.5, 1 - Chapter 10 Class 7 Practical Geometry - Part 3
Ex 10.5, 1 - Chapter 10 Class 7 Practical Geometry - Part 4
Ex 10.5, 1 - Chapter 10 Class 7 Practical Geometry - Part 5


Transcript

Ex 10.5, 1 Construct the right angled ∆PQR, where m∠Q = 90°, QR = 8cm and PR = 10 cm. First we draw a rough sketch We follow these steps Steps of construction 1. Draw a line segment QR of length 8 cm 2. Now, we draw 90° from point Q Check Ex 11.1, 1 of Chapter 11 Class 9 NCERT to see how to draw 90° 3. Taking R as center, 10 cm as radius, we draw an arc Let the point where arc intersects the ray be point P 4. Join PR and label the sides Thus, Δ PQR is the required triangle

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Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 12 years. He provides courses for Maths and Science at Teachoo.