Example 7 - Congruence of Triangles

Last updated at April 16, 2024 by

Example 7 - In Fig 7.26, can you use ASA congruence rule

Example 7 - Chapter 7 Class 7 Congruence of Triangles - Part 2
Example 7 - Chapter 7 Class 7 Congruence of Triangles - Part 3

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Example 7 In Fig 7.26, can you use ASA congruence rule and conclude that ∆AOC ≅ ∆BOD?Here, ∠AOC = ∠BOD 30° = ∠BOD ∠BOD = 30° In ∆AOC, By Angle Sum Property, ∠A + ∠AOC + ∠C = 180° ∠A + 30° + 70° = 180° ∠A + 100° = 180° ∠A = 180° − 100° ∠A = 80° In ∆BOD, By Angle Sum Property, ∠B + ∠BOD + ∠D = 180° ∠B + 30° + 70° = 180° ∠B + 100° = 180° ∠B = 180° − 100° ∠B = 80° From (1) & (2) ∠A = ∠B = 80° In ∆AOC and ∆BOD, ∠A = ∠B AC = BD ∠C = ∠D ∴ ∆AOC ≅ ∆BOD

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Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science, Social Science, Physics, Chemistry, Computer Science at Teachoo.