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  1. Chapter 7 Class 7 Congruence of Triangles
  2. Serial order wise
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Transcript

Example 7 In Fig 7.26, can you use ASA congruence rule and conclude that ∆AOC ≅ ∆BOD?Here, ∠AOC = ∠BOD 30° = ∠BOD ∠BOD = 30° In ∆AOC, By Angle Sum Property, ∠A + ∠AOC + ∠C = 180° ∠A + 30° + 70° = 180° ∠A + 100° = 180° ∠A = 180° − 100° ∠A = 80° In ∆BOD, By Angle Sum Property, ∠B + ∠BOD + ∠D = 180° ∠B + 30° + 70° = 180° ∠B + 100° = 180° ∠B = 180° − 100° ∠B = 80° From (1) & (2) ∠A = ∠B = 80° In ∆AOC and ∆BOD, ∠A = ∠B AC = BD ∠C = ∠D ∴ ∆AOC ≅ ∆BOD

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Davneet Singh
Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 8 years. He provides courses for Maths and Science at Teachoo. You can check his NCERT Solutions from Class 6 to 12.