Example 6 - Congruence of Triangles

Last updated at August 14, 2026 by

Example 6 - By applying ASA congruence rule, it is to be established

Example 6 - Chapter 7 Class 7 Congruence of Triangles - Part 2

Remove Ads
Teachoo · Class 7 Explore Class 7

Transcript

Example 6 - Chapter 7 Class 7 Congruence of Triangle - NCERT By applying ASA congruence rule, it is to be established that ∆ ABC ≅∆QRP and it is given that BC = RP. What additional information is needed to establish the congruence? Given, BC = RP And, ∆ABC ≅ ∆QRP (By ASA Congruence Rule) Since it is ASA Congruence rule, We need Angle Side Angle Here, side is BC. So, Angle on either side of it should be equal. Therefore, ∠B = ∠R ∠C = ∠P

Davneet Singh's photo - Co-founder, Teachoo

Made by

Davneet Singh

Davneet Singh is an IIT Kanpur graduate and has been teaching for 16+ years. At Teachoo, he breaks down Maths, Science and Computer Science into simple steps so students understand concepts deeply and score with confidence.

Many students prefer Teachoo Black for a smooth, ad-free learning experience.