![Example 3 - Chapter 7 Class 7 Congruence of Triangles - Part 2](https://d1avenlh0i1xmr.cloudfront.net/9c231753-a2a7-4bd7-8f2c-49eb0d8fa2f9/slide5.jpg)
![Example 3 - Chapter 7 Class 7 Congruence of Triangles - Part 3](https://d1avenlh0i1xmr.cloudfront.net/3f7d3dc0-b89f-4ae9-8c17-edc62c5a1d0f/slide6.jpg)
Examples
Last updated at April 16, 2024 by Teachoo
Example 3 - Chapter 7 Class 7 NCERT In Fig 7.13, AD = CD and AB = CB. (i) State the three pairs of equal parts in ∆ABD and ∆CBD. In ∆ABD and ∆CBD AB = CB (Given) AD = CD (Given) BD = BD (Common) Example 3 In Fig 7.13, AD = CD and AB = CB. (ii) Is ∆ABD ≅ ∆CBD? Why or why not? In ∆ABD and ∆CBD AB = CB (Given) AD = CD (Given) BD = BD (Common) ∴ ∆ABD ≅ ∆CBD (SSS Congruence Rule) Example 3 In Fig 7.13, AD = CD and AB = CB. (iii) Does BD bisect ∠ABC? Give reasons. Since ∆ABD ≅ ∆CBD By CPCT, ∠ABD = ∠CBD Hence, BD divides ∠ABC into two equal parts ∴ BD bisects ∠ABC