Let’s take an Example
283 is a 3 digit number.
Digits at hundreds place = 2
Digits at tens place = 8
Digit at units place of = 3
So, the number will be
Number = (Digits at hundreds place × 100)
+ (Digits at ten place × 10) + (Digit at units place × 1)
= 2 × 100 + 8 × 10 + 3 × 1
= 200 + 80 + 3
= 283
To generalize
Number |
Digits are interchanged |
Let number be abc
So, Digit at hundreds place = a Digit at tens place = b & Digit at unit place = c
Number
= (100 × Digit at hundreds place)
= (100 × a) + (10 × b) + (1 × c) = 100a + 10b + c |
Thus, number will be cba
So, Digit at hundreds place = c Digit at tens place = b & Digit at unit place = a
Number
= (100 × Digit at hundreds place)
= (100 × c) + (10 × b) + (1 × a) = 100c + 10b + a |