Forming Linear Equations - Two digit number

Chapter 2 Class 8 Linear Equations in One Variable
Concept wise

Let’s take an Example

283 is a 3 digit number.

Digits at hundreds place = 2

Digits at tens place = 8

Digit at units place of = 3

So, the number will be

Number = (Digits at hundreds place × 100)
+ (Digits at ten place × 10) + (Digit at units place × 1)

= 2 × 100 + 8 × 10 + 3 × 1

= 200 + 80 + 3

= 283

To generalize

 Number Digits are interchanged Let number be     abc   So, Digit at hundreds place = a       Digit at tens place = b   & Digit at unit place = c   Number   = (100 × Digit at hundreds place)        + (10 × Digit at tens place)         +  (1 × Digit at units place)   = (100 × a) + (10 × b) + (1 × c)   = 100a + 10b + c Thus, number will be     cba   So, Digit at hundreds place = c       Digit at tens place = b   & Digit at unit place = a   Number   = (100 × Digit at hundreds place)        + (10 × Digit at tens place)         +  (1 × Digit at units place)      = (100 × c) + (10 × b) + (1 × a)      = 100c + 10b + a

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