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  1. Chapter 2 Class 8 Linear Equations in One Variable
  2. Serial order wise
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Ex 2.4, 7 Hasan buys two kinds of cloth materials for school uniforms, shirt material that costs him Rs 50 per metre and trouser material that costs him Rs 90 per metre. For every 2 meters of the trouser material he buys 3 metres of the shirt material. He sells the materials at 12% and 10% profit respectively. His total sale is Rs 36,660. How much trouser material did he buy?Given, Cost of shirt material = Rs 50 per meter & Cost of trouser material = Rs 90 per meter For every 3 meters of the shirt material, he buys 2 meter of the trouser material. (๐‘†โ„Ž๐‘–๐‘Ÿ๐‘ก ๐‘š๐‘Ž๐‘ก๐‘’๐‘Ÿ๐‘–๐‘Ž๐‘™ ๐‘๐‘ข๐‘Ÿ๐‘โ„Ž๐‘Ž๐‘ ๐‘’๐‘‘)/(๐‘‡๐‘Ÿ๐‘œ๐‘ข๐‘ ๐‘’๐‘Ÿ ๐‘š๐‘Ž๐‘ก๐‘’๐‘Ÿ๐‘–๐‘Ž๐‘™ ๐‘๐‘ข๐‘Ÿ๐‘โ„Ž๐‘Ž๐‘ ๐‘’๐‘‘)=3/2 Let shirt material purchased = 3๐‘ฅ meters & trouser material purchased = 2๐‘ฅ meters Shirt material Cost price = Cost of 1 meter ร— Quantity = 50 ร— 3๐‘ฅ = (50 ร— 3) ๐‘ฅ = 150๐‘ฅ Hasan sells the shirt material at 12% profit Profit = 12% ร— Cost price = 12/100ร—150๐‘ฅ = 18๐‘ฅ Sell Price = Cost price + Profit = 150๐‘ฅ + 18๐‘ฅ = 168๐‘ฅ Let shirt material purchased = 3๐‘ฅ meters & trouser material purchased = 2๐‘ฅ meters Shirt material Cost price = Cost of 1 meter ร— Quantity = 50 ร— 3๐‘ฅ = (50 ร— 3) ๐‘ฅ = 150๐‘ฅ Hasan sells the shirt material at 12% profit Profit = 12% ร— Cost price = 12/100ร—150๐‘ฅ = 18๐‘ฅ Trouser material Cost price = Cost of 1 meter ร— Quantity = 90 ร— 2๐‘ฅ = (90 ร— 2) ๐‘ฅ = 180๐‘ฅ Hasan sells the trouser material at 10% profit Profit = 10% ร— Cost price = 10/100ร—180๐‘ฅ = 18๐‘ฅ Trouser material Cost price = Cost of 1 meter ร— Quantity = 90 ร— 2๐‘ฅ = (90 ร— 2) ๐‘ฅ = 180๐‘ฅ Hasan sells the trouser material at 10% profit Profit = 10% ร— Cost price = 10/100ร—180๐‘ฅ = 18๐‘ฅ Therefore, Sell price of shirt material = 168๐‘ฅ and Sell price of trouser material = 198๐‘ฅ Given that Hasan's total sale amount = Rs 36,600 Sell price of shirt material + Sell price of trouser material = Rs 36,600 168๐‘ฅ + 198๐‘ฅ = 36,600 366๐‘ฅ = 36,600 ๐‘ฅ = 36600/366 ๐‘ฅ = 100 โˆด Quantity of the trouser material Hasan buys = 2๐‘ฅ = (2 ร— 100) = 200 meters

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Davneet Singh
Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 8 years. He provides courses for Maths and Science at Teachoo. You can check his NCERT Solutions from Class 6 to 12.