Ex 2.1, 8 - Solve 2x/3 + 1 =7x /15 + 3  - Chapter 2 NCERT Maths - Ex 2.1

part 2 - Ex 2.1, 8 - Ex 2.1 - Serial order wise - Chapter 2 Class 8 Linear Equations in One Variable

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Transcript

Ex 2.1, 8 Solve the following equations and check your results. 2๐‘ฅ/3+1=7๐‘ฅ/15+3 2๐‘ฅ/3+1=7๐‘ฅ/15+3 (๐Ÿ๐’™ + ๐Ÿ‘)/๐Ÿ‘=(๐Ÿ•๐’™ + ๐Ÿ‘ ร— ๐Ÿ๐Ÿ“)/๐Ÿ๐Ÿ“ (2๐‘ฅ + 3)/3=(7๐‘ฅ + 45)/15 15 (2x + 3) = 3 (7x + 45) 30x + 45 = 3 (7x + 45) 30x + 45 = 21x + 135 30x โˆ’ 21x + 45 = 135 9x + 45 = 135 9x = 135 โˆ’ 45 9x = 90 x = 90/9 x = 10 Check:- โˆด LHS = RHS Hence Verified. L.H.S 2๐‘ฅ/3+1=(2 ร— 10 + 1 )/3 = (20 + 3)/3=23/2 R.H.S (7๐‘ฅ )/15+3=(7 ร— 10 )/15+3=14/3+3 = (14 + 9)/3=23/3

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